Question

√5×(2√3-4√2)-√60=?
Cum se rezolvă?

Answer 1

$\sqrt{5} (2\sqrt{3} - 4 \sqrt{2}) - \sqrt{60}$ 
= $(2\sqrt{3inmultit5} - 4 \sqrt{2inmultit5}) - \sqrt{60}$
= $(2\sqrt{15} - 4 \sqrt{10}) - \sqrt{60}$
= $(\sqrt{15inmultit2^2} - 4 \sqrt{10}) - \sqrt{60}$
= $(\sqrt{15inmultit4} - 4 \sqrt{10}) - \sqrt{60}$
= $(\sqrt{60} - 4 \sqrt{10}) - \sqrt{60}$
= $(\ 0 -4\sqrt{10})$
= $(\ - 4 \sqrt{10})$

Answer 2

$\sqrt5(2\sqrt3-4\sqrt2)-\sqrt{60}=\\ 2*\sqrt5*\sqrt3-4*\sqrt5*\sqrt2-\sqrt{4*15}=\\ \not2\sqrt{15}-4\sqrt{10}-\not2\sqrt{15}=-4\sqrt10$