Question

5^3:[2^5-(7x2^7:14-7^0):3^2]

Answer 1

${5}^{3} \div [ {2}^{5} - (7 \times {2}^{7} \div 14 - {7}^{0} ) \div {3}^{2} ]$

$= 125 \div [32 - (7 \times 128 \div 14 - 1) \div 9]$

$= 125 \div [32 - (896 \div 14 - 1) \div 9]$

$= 125 \div [32 - (64 - 1) \div 9]$

$= 125 \div (32 - 63 \div 9)$

$= 125 \div (32 - 7)$

$= 125 \div 25$

$= 5$