Question

5+5×{5+5:[45:5-(36:x+4×1)]+6×0}=55

Answer 1

5 + 5 × { 5 + 5 : [ 45 : 5 - ( 36 : x + 4 × 1 ) ] + 6 × 0 } = 55

5 + 5 × { 5 + 5 : [ 45 : 5 - ( 36 : x + 4 ) ] + 6 × 0 } = 55

5 + 5 × { 5 + 5 : [ 9 - ( 36 : x + 4 ) ] + 0 } = 55

5 × { 5 + 5 : [ 9 - ( 36 : x + 4 ) ] + 0 } = 55 - 5

5 × { 5 + 5 : [ 9 - ( 36 : x + 4 ) ] + 0 } = 50

{ 5 + 5 : [ 9 - ( 36 : x + 4 ) ] + 0 } = 50 : 5

{ 5 + 5 : [ 9 - ( 36 : x + 4 ) ] + 0 } = 10

{ 5 : [ 9 - ( 36 : x + 4 ) ] + 0 } = 10 - 5

{ 5 : [ 9 - ( 36 : x + 4 ) ] + 0 } = 5

[ 9 - ( 36 : x + 4 ) + 0 ] = 5 : 5

[ 9 - ( 36 : x + 4 ) + 0 ] = 1

( 36 : x + 4 ) + 0 = 9 - 1

( 36 : x + 4 ) + 0 = 8

36 : x + 4 = 8 - 0

36 : x + 4 = 8

36 : x = 8 - 4

36 : x = 4

x = 36 : 4

x = 9

Answer 2

$5 + 5 \times (5 + 5 \div (9 - (36 \div x + 4)) + 0) = 55 \\ 5 \times (5 + 5 \div (9 - (36 \div x + 4)) + 0) = 50 \\ 5 + 5 \div (9 -( 36 \div x + 4)) = 10 \\ 5 \div (9 - ( 36 \div x + 4)) = 5 \\ 9 - (36 \div x + 4) = 1 \\ 36 \div x + 4 = - 8 \\ 36 \div x = - 4 \\ x = - 4 \div 36 \\ x = \ - \frac{4}{36 } \\ x = - \frac{1}{9}$
succes la scoala !!