Question

5,6 trebuie rezolvate.

Answer 1

5)a-nr.fetelor b-nr.baietilor a=60supra 100·b a+b=32 6supra10·b + b =32 |·10 16b=320 b=20(baieti) a=12(fete) 6)x,y-nr cautate x+y=513 x/y=50 rest 3 <=> x=50y+3 50y+3+y=513 => 51y=513–3 => 51y=510 => y=510/51 => y=10 x=50·10+3 => x=503