Question

5 A si B va rog.Daca se poate,si 6

Answer 1

a=11√3-5√3+7√3-9√3+8√3=√3(11-5+7-9+8)=12√3
b=12√3-6√3+8√3-10√3-5√3=√3(12-6+8-10-5)=-√3
(2a-3b)/(a+2b)=[2*12√3-3(-√3)]/(12√3-2√3)=27√3/10√3=27/10


a=10√6-12√6+8√6-5√6+9√6-7√6=3√6
b=-9√6+13√6-15√6+8√6-3√6+2√6=-4√6
(3a+2b)/(2a-b)=[3*3√6+2(-4√6)]/(2*3√6+4√6)=√6/10√6=1/10


6.
a)√32-√50+√8-√98+√242=4√2-5√2+2√2-7√2+11√2=5√2
c)√48-√75+√12+√243-√147=4√3-5√3+2√3+9√3-7√3=3√3