5. Descompuneți în factori prin scoaterea factorului comun:
a) 3x(x - 2) + (x - 2)2 – 5(x-2);
b) (x - 1)(x-2) + 4(x - 1)2 - 4x(x - 1);
c)(x-4)(3x + 7) - (x - 4)(4x + 2) + 3(x - 4);
d) (2x + 1)2 – (3x − 2)(2x + 1) + 3x(2x + 1);
e) (4x + 5)(3x + 2)2 – (3x + 2)2 + 2(x + 4)(3x + 2)?;
f) (5x - 3)(3x + 4) - 2(3x + 4)2 + 3x(3x + 4)
Răspunsuri la întrebare
Răspuns: Sper ca te-am ajutat! Mult noroc la scoala!
Explicație pas cu pas:
Răspuns: Ai rezolvarea mai jos
Explicație pas cu pas:
Salutare!
(a)
3x(x - 2) + (x - 2)² - 5(x-2) =
(x - 2)(3x + x - 2 - 5) =
(x - 2)(4x - 7)
(b)
(x - 1)(x - 2) + 4(x - 1)² - 4x(x - 1) =
(x - 1)[(x-2) + 4(x - 1) - 4x] =
(x - 1)(x - 2 + 4x - 4 - 4x) =
(x - 1)(x - 6)
(c)
(x - 4)(3x + 7) - (x - 4)(4x + 2) + 3(x - 4) =
(x - 4)[(3x + 7) - (4x + 2) + 3] =
(x - 4)(3x + 7 - 4x - 2 + 3) =
(x - 4)(8 - x)
(d)
(2x + 1)² – (3x − 2)(2x + 1) + 3x(2x + 1) =
(2x + 1)[2x + 1 – (3x − 2) + 3x ] =
(2x + 1)(2x + 1 – 3x + 2 + 3x ) =
(2x + 1)(2x + 3)
(e)
(4x + 5)(3x + 2)² - (3x + 2)² + 2(x + 4)(3x + 2)² =
(3x + 2)²[(4x + 5) - 1 + 2(x + 4)] =
(3x + 2)²(4x + 5 - 1 + 2x + 8) =
(3x + 2)²(6x + 12)
(f)
(5x - 3)(3x + 4) - 2(3x + 4)² + 3x(3x + 4) =
(3x + 4)[(5x - 3) - 2(3x + 4) + 3x] =
(3x + 4)(5x - 3 - 6x - 8 + 3x) =
(3x + 4)(2x - 11)
==pav38==