Question

5 grame de zinc reactioneaza de acid azotic de concentratie 25%,obtinanduse azotat de zinc si hidrogen .calculati:a)masa solutiei de acid azotic consumat in reactieb)volumul de hidrogen degajat
URGENT VA ROG!DAU COROANA​

Answer 1

Răspuns:

A,Zn= 65g/mol

miu,HNO3=63g/mol

V,m=22,4 l/mol

65g,,,,,,2x63g............................22,4 l

Zn  +  2HNO3-----> Zn(NO3)2 + H2

5g............x..........................................y

x=9,69g HNO3=md

y= 8 l

c= mdx100/ms---> ms= 9,69x100/25g=38,76g solutie HNO3

Explicație: