Question

5 moli soda caustica si 600g apa

Answer 1

banuiesc ca conc. procentuala a solutiei formata prin dizolvarea a 5 moli soda caustica in 600 g apa...!!???

soda caustica = NaOH, M. = 40 g/mol

nr.moli = masa/M => m = nr.molixM. = 5x40 = 200 g NaOH

md = 200 g, c%=?%

m.apa = 600 g

ms = md+m.apa = 200+600 = 800 g sol. NaOH

stim ca c% = mdx100/ms

= 200x100/800 = 25%