Question

5. Pentru fiecare dintre
triunghiurile de mai jos,
calculează valorile: sina,
cosa, tga, ctga.
A
b)
B
a)
4.5
ON
3.5
5,5
c
B
А
S
С
a))
Va rog. URGENT!
MULTUMESC​

Answer 1

Răspuns:

Explicație pas cu pas:

a) sinα=AC/BC=4,5/5=9/10=0,9

 cosα=√1-0,81=√0,19=0,436

tgα=0,9/0,436≅2,063         ctg α=0,48

b)

cosα=AB/BC=3,5/5,5=0,63

sinα=√1-cos²α=√1-0,39=0,77

tgα=0,77/0,63=1,22

ctgα=0,63/0,77==0,81

Answer 2

a) sina=cateta opusa/ipotenuza= 4,5/5=
Din teorema lui pitagora=> 5*2=4,5*2+AB*2=>AB=radical19\2
cosa=cateta alaturata/ipotenuza=radical19/2/5=radical19/10
tga=cateta opusa/alaturata=9/2/radical19/2=9/radical19
ctga=cateta alaturata/cateta opusa=radical19/2/9/2=radical19/9
b) Din teorema lui pitagora=>AC*2=(11/2)*2-(7/2)*2=121/4-49/4=72/4=>AC=3radical2
sina=3radical2/11/2=6radical2/11
cosa=7/2/11/2=7/11
tga=3radical2/7/2=6radical2/7
ctga=7/2/3radical2=7/6radical2
Am notat cu “\” linia de fractie si cu”*” puterile.