Question

5 perechi cu 2 nr pt cmmmc.
5perechi cu 3 nr pt cmmdc.

Va rog repede coroana și 15 puncte.

Answer 1

1.

34 = 2 × 17

51 = 3 × 17

cmmmc (34; 51) = 2 × 3 × 17 = 102

2.

48 = 2⁴ × 3

160 = 2⁵ × 5

cmmmc (48; 160) = 2⁵× 3 × 5 = 480

3.

120 = 2³ × 3 × 5

34 = 2 × 17

cmmmc (120; 34) = 23 × 3 × 5 × 17 = 2.040

4.

119 = 7 × 17

220 = 2² × 5 × 11

cmmmc (119; 220) = 2² × 5 × 7 × 11 × 17 = 26.180

5.

48 = 2⁴ × 3

176 = 2⁴ × 11;

cmmmc (48; 176) = 2₄ × 3 × 11 = 528

1.

3 numere cmmdc

12 = 2² × 3

15 = 3 × 5

20 = 2² × 5

La c.m.m.d.c.(cel mai mare divizor comun) se iau toate numerele comune la puterea cea mai mica.

c.m.m.d.c. = 1

2.

50 = 5 × 2 × 5 = 2 × 5²

20 = 2² × 5

65 = 5 × 13

c.m.m.d.c. = 5

3.

30 = 2 × 3 × 5

40 =  2 la 3⁵

50 = 2 × 5²

c.m.m.d.c. = 2 × 5 = 10

4.

63 = 3² × 7

72 = 3² ×  2³

81 = 3⁴

c.m.m.d.c. = 3² = 9