Question

(5/rad28-2rad7/7+3/2rad7)÷1/rad14​

Answer 1

Răspuns:

Explicație pas cu pas:

$(\frac{5}{\sqrt28} } -\frac{2\sqrt{7} }{7} +\frac{3}{2\sqrt{7} } ):\frac{1}{\sqrt{14} } =\\ \\ =(\frac{5}{2\sqrt{7} } } -\frac{2\sqrt{7} }{7} +\frac{3}{2\sqrt{7} } ):\frac{1}{\sqrt{14} } =\\ \\ =(\frac{1}{\sqrt{7} } -\frac{2\sqrt{7} }{7} )\cdot\sqrt{14} =\\ \\ =(\frac{\sqrt{7} }{7} -\frac{2\sqrt{7} }{7} )\cdot\sqrt{14} =\\ \\ =\frac{\sqrt{7} }{7} \cdot\sqrt{7} \cdot\sqrt{2} =\\ \\ =\sqrt{2}$