Question

5 radical 2 +7 radical 2-13 radical 2=
2 radical 3-7 radical 3+5 radical 7-6 radical 7+1=
2 radical 75+3 radical 48-2 radical 300=
4 radical 5. (-2 radcal 7). (- radical3)=
(3 radical 2-2 radical 7 +1). 2 radical 2=
(3 radical 3+5 radical 2-3). ( radical 3- 2 radical 5)=
20 radical 10: (-5 radical 5)=
(15 radical 10 + 25 radical 5 -5 radical 35) : 5 radical 5=

Answer 1

rad2•(5+7-13) = -rad2
rad3•(2-7) + rad7•(5-6) + 1 = 1 - 5rad3 - rad7
10rad3 + 12rad3 - 20rad3 = 2rad3
8rad105
12 - 4rad14 + 2rad2 = 2•(6 - 2rad14 + rad2)
9 - 6rad15 + 5rad6 - 10rad10 - 3rad3 + 6rad5
20rad2•rad5 : (-5rad5) = -4rad2
5rad5•(3rad2 + 5 - rad7) : 5rad5 = 3rad2 - rad7 + 5