Question

(5 - sqrt(24))/(sqrt(32)) + (8sqrt(6) - 3)/(2sqrt(27)) - (6 + 3sqrt(6))/(6sqrt(12)) - (4 + sqrt(24))/(3sqrt(8))
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Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Explicație pas cu pas:

$\dfrac{5 - \sqrt{24} }{ \sqrt{32} } + \dfrac{8 \sqrt{6} - 3}{2 \sqrt{27} } - \dfrac{6 + 3 \sqrt{6} }{6 \sqrt{12} } - \dfrac{4 + \sqrt{24} }{3 \sqrt{8} } =$

$= \dfrac{^{ \sqrt{2})}5 - 2\sqrt{6} }{ 4\sqrt{2} } + \dfrac{^{ \sqrt{3})}8 \sqrt{6} - 3}{6 \sqrt{3} } - \dfrac{^{ \sqrt{3})}6 + 3 \sqrt{6} }{12 \sqrt{3} } - \dfrac{^{ \sqrt{2}) }4 + 2\sqrt{6} }{6 \sqrt{2} }$

$= \dfrac{5 \sqrt{2} - 4\sqrt{3} }{8} + \dfrac{24 \sqrt{2} - 3 \sqrt{3}^{(3} }{18} - \dfrac{6 \sqrt{3} + 9 \sqrt{2}^{(3} }{36} - \dfrac{4 \sqrt{2} + 4\sqrt{3} ^{(4}}{12}$

$= \dfrac{^{3)} 5 \sqrt{2} - 4\sqrt{3} }{8} + \dfrac{^{4)}8 \sqrt{2} - \sqrt{3} }{6} - \dfrac{^{2)}2 \sqrt{3} + 3 \sqrt{2} }{12} - \dfrac{ ^{8)}\sqrt{2} + \sqrt{3} }{3}$

$= \dfrac{15 \sqrt{2} - 12\sqrt{3} + 32 \sqrt{2} - 4\sqrt{3} - 4 \sqrt{3} - 6 \sqrt{2} - 8\sqrt{2} - 8\sqrt{3}}{24}$

$= \dfrac{33 \sqrt{2} - 28\sqrt{3}}{24} = \dfrac{11 \sqrt{2}}{8} - \dfrac{7\sqrt{3}}{6}$