Question

(-5 supra 3 ) +(-5 supra 6) + 5 supra 2 + (5 supra 12 )​

Answer 1

$\it -\dfrac{5}{3}+\dfrac{-5}{6}+\dfrac{5}{2}+\dfrac{5}{12}=5\Big(-\dfrac{^{4)}1}{\ 3}-\dfrac{^{2)}1}{\ 6}+\dfrac{^{6)}1}{\ 2}+\dfrac{1}{12}\Big)=5\cdot\dfrac{-4-2+6+1}{12}=\\ \\ \\ =5\cdot\dfrac{1}{12}=\dfrac{5}{12}$