Question

5) x = 3radical7/7 - 4radic7/3 + 2radical7/2 Y=4radical3- 3radical2/12 - 3radical7 + 7radical3/21 - 4radical7 - 7radical2/28

Vă rog să îmi explicați și mie!!!

Answer 1

Explicație pas cu pas:

$x = \dfrac{^{6)} 3 \sqrt{7} }{7} - \dfrac{^{14)}4 \sqrt{7}}{3} + \dfrac{^{21)}2 \sqrt{7} }{2} = \\ = \dfrac{18 \sqrt{7} - 56 \sqrt{7} + 42 \sqrt{7} }{42} = \dfrac{4 \sqrt{7}^{(2} }{42} = \dfrac{2 \sqrt{7} }{21}$

$y = 4 \sqrt{3} - \dfrac{3 \sqrt{2} ^{(3}}{12} - 3 \sqrt{7} + \dfrac{7 \sqrt{3}^{(7}}{21} - 4 \sqrt{7} - \dfrac{7 \sqrt{2}^{(7)}}{28} = \\ = \Big(^{3)} 4 \sqrt{3} + \dfrac{\sqrt{3} }{3}\Big) - \Big(\dfrac{\sqrt{2} }{4} + \dfrac{\sqrt{2} }{4}\Big) - \Big(3 \sqrt{7} + 4 \sqrt{7}\Big) \\ = \Big(\dfrac{12 \sqrt{3} + \sqrt{3} }{3}\Big) - \Big(\dfrac{2\sqrt{2}^{(2} }{4}\Big) - \Big(7 \sqrt{7}\Big) = \dfrac{13 \sqrt{3} }{3} - \dfrac{\sqrt{2} }{2} - 7 \sqrt{7}$