Question

5(y-2)+3=38
9+2(14-y)=15

Answer 1

5(y-2)+3=38
5y-10+3=38
5y-7= 38
5y=38+7
5y =45
y=45/9
y=5

Answer 2

$\displaystyle a).5(y-2)+3=38 \\ 5y-10+3=38 \\ 5y=38+10-3 \\ 5y=45 \\ y= \frac{45}{5} \\ y=9$
$\displaystyle b).9+2(14-y)=15 \\ 9+28-2y=15 \\ -2y=15-9-28 \\ -2y=-22 \\ y= \frac{-22}{-2} \\ y=11$