Question

50 puncte
Ecuatia in N​

Answer 1

Am atasat o rezolvare.

Answer 2

(x+1)/2-3/(y+1)=4 | * 2(y+1)

(x+1)(y+1)-6=8(y+1)

(x+1)(y+1)=8(y+1)+6

x+1=(8(y+1)+6)/(y+1)

x=(8(y+1)+6)/(y+1) - 1

x=(8y+8+6)/(y+1) - (y+1)/(y+1)

x=(8y+14-y-1)/(y+1)

x=(7y+13)/(y+1)

x=(7(y+1)+6)/(y+1)  

(y+1) | 7(y+1) => (y+1) | 6 => y+1 ∈{ 1 ,2 ,3, 6 }  => y∈{0,1,2,5}

y=0=> x= (7y+13)/(y+1)=> x= 13/1=13

y=1=> x= (7y+13)/(y+1)=> 20/2=10

y=2=> x= 27/3=9

y=5=> x=48/6=8

(y,x)∈{(0,13);(1,10);(2,9);(5,8)}