Question

500 g solutie de HCl cu concetratia procentula c=36% reactioneaza cu Al2O3.
1)ce prdusi se obtin si in ce cantitati
2) masa apei din solutia finala
3)concentratia procentuala a solutiei finale

Answer 1

6HCl + Al₂O₃ = 2AlCl₃ + 3H₂O

c= Md/Ms * 100
Md= Ms*c/100 = 500*36/100 = 180 g HCl.

M HCl= 36.5
M AlCl₃ = 187.5

6*36.5/180 = 2*187.5/x
x= 180*2*187.5/6*36.5
x= 180 g AlCl₃

M H₂O = 2*16 = 18

6*36.5/180 = 3*18/x
x= 180*3*18/6*36.5
x≈ 44.38 g H₂O