Question

500g KCL3 de puritate 80% se descompune . de aflat masele produsiilor de reactie si numarul de moli​

Answer 1

Răspuns:

KClO3

Explicație:

-se afla masa de KClO3 pura

mp=p.mi :100

mp=80 . 500 :100=400 g KClO3 pur

  400g          xg            yg

     2KClO3=2 KCl   + 3O2

 2.122,5g      2.74,5g   3.32g

x=400.2 .74,5 : 2 .122,5=243,3 g KCl

n= 243,3g : 74,5g/moli=3,26 moli KCl

y=400 .96 :245=156,73 g O

n= 156,73g : 32g/moli=4,89 moli oxigen

MKClO3=39 +35,5 +3.16=122,5---->122,5g/moli

MKCl=39+ 35,5=74,5---->74,5g/moli

[ verifica calculele ! ]