Question

(5¹⁷×5¹⁸+7²³:7¹⁵):(7×7²×7⁵+5⁵⁰:5¹⁵)​

Answer 1

$( {5}^{17} \times {5}^{18} + {7}^{23} \div {7}^{15} ) \div (7 \times {7}^{2} \times {7}^{5} + {5}^{50} \div {5}^{15} )$

$= ( {5}^{17 + 18} + {7}^{23 - 15} ) \div ( {7}^{1 + 2 + 5} + {5}^{50 - 15} )$

$= ( {5}^{35} + {7}^{8} ) \div ( {7}^{8} + {5}^{35} )$

$= 1$