Question

56 gr C6H6 +nitrare
A) ec. R ch
B) masa soluției de hno3 c=63%
C) masa de nitrobenzen dacă n=80%
C6H6+Hno3----H2so4---- C6H5 -no2+ H2O

Urgeeeent

Answer 1

M.C6H6= (6X12gC+6gH)/mol=78g/mol
M,HNO3=)(1gH+14gN+48gO)mol= 63g/mol
M, nitrobenzen=(6x12gC+5gH+14gN+32gO)/mol=123g/mol
- din reactie,
1mol  benzen........1mol HNO3........1mol nitrobenzen
78g........................63g.........................123g
56...............................m...................................m'

m=45,23gHNO3-->este md din solutie  63/100=45,23/ms---> ms=
m'=88,3g nitrobenzen , daca randamentul este 100%; fiind mai mic, se va obtine o masa mai mica-->m'=88,3x80/100------------------->
calculeaza !!!!!