Question

(5la puterea2*5la puterea3*5la puterea4)la puterea2 impartit (5la puterea3)la puterea5-(11la puterea 7)la puterea2 impartit (11 la puterea2)la puterea2 impartit (11la puterea 7* 11la puterea0 * 11)=4, Adevarat?,

Answer 1

(5^2*5^3*5^4)^2: (5^3)^5 - (11^7)^2 : (11^2)^2 : (11^7*11^0*11) =

(5^9)^2 : 5^15 - 11^14 : 11^4 : (11^7*1*11) = 5^18 : 5^15 - 11^14 : 11^4 : 11^8 =

5^3 - 11^2 = 125 -121 = 4