Question

5radical3+3×{4radical2+4[3radical3+2(radical3-3radical2)]}÷20​

Answer 1

5radical3 + 3×{4radical2 + [3radical3 + 2(radical3 - 3radical2)]}=

=5radical3+3×[4radical2+4(3radical3+2radical3-6radical2)]=

=5radical3+3×(4radical2+12radical3+8radical3-24raducal2)

$5 \sqrt{3 } + 3 \times (4 \sqrt{2} + 12 \sqrt{3} + 8 \sqrt{3} - 24 \sqrt{2} )$

$5 \sqrt{3} + 3 \times (20 \sqrt{3} - 2 0 \sqrt{2} )$

$5 \sqrt{3 } +60 \sqrt{3} - 60 \sqrt{2}$

$60( \sqrt{3} - \sqrt{2} ) + 5 \sqrt{3}$