Question

5x+1 supra x+1= x+2 supra x

Answer 1

(x+1)(x+2)=x(5x+1), x≠0 si de -1
x^2+3x+2=5x^2+x
4x^2 -2x -2=0 I :2
2x^2 -x -1 = 0
x1,2 = 1+/- rad(1+8)
x1=1+3=4
x2=1-3= -2

Answer 2

fiind vorba de rapoarte egale
produsul mezilor = produsul extremilor
(5x+1)x=(x+1)(x+2)
5X^2+x=x^2+2x+x+2
4x^2-2x-2=0|:2
2x^2-x-1=0
a=2
b=-1
c=-1
∆= b^2-4ac
∆=1+8
∆=9
x1=(1-3)/4
x1=-1/2
x2=1
sau 2x^2-x-1=2x^2+x-2x-1=(x-1)(2x+1)