Question

5xy²-(8x³y⁴):(2x²y²)+x•3y²;9x³•(-2xy²)-14x•y²•x³+(-5x²y²)•(-x²);a²x-3a•(-2ax)+5x•(-0,2a²);-2\3x•(-3x)²+5\9x la puterea 6:(20\27x³)-0,6x•(-5x²);6\5x•(-x)²+1\4x la puterea 5:(0,5x²)+(-1\2x)²•(-x);3\4x•(-9\8x)+(4x²)²:(-x)²-9•(-1\3x)²

Answer 1

[tex]5xy^2-4xy^2+3xy^2=xy^2+3xy^2=4xy^2\\ -18x^4y^2-14x^4y^2+5x^4y^2=-27x^4y^2\\ a^2x+6a^2x-a^2x=6a^2x\\ -\frac{2}{3}x\cdot9x^2+\frac{5}{9}x^6:(\frac{20}{27}x^3)+3x^3=\\ -6x^3+\frac{5}{9}\cdot\frac{27}{20}x^3+3x^3= -^{4)} 3x^3+\frac{3}{4}x^3=-\frac{9}{4}x^3\\ 1,2x^3+0,5x^3-0,25x^3=1,45x^3\\ -\frac{27}{32}x^2+16x^2-x^2=-\frac{27}{32}x^2+ ^{32)} 15x^2=\frac{453}{32}x^2 [/tex]