Question

(6+12+18+24+...+600)^2:(3+6+9+12+...+300):(1+2+3+...+100)= ?
Dau Coroana

Answer 1

$(6+12+...+600)^2=[6(1+2+...+100)]^2= \\ 36(1+2+...+100)(1+2+...+100)$
$3+6+9+...+300=3(1+2+3+...+100)$

Calculul devine
$36(1+2+..100)(1+2+..100):[3(1+2+..+100)]:(1+2+..+100)$

Parantezele cu (1+2+3...+100) se simplifica toate.
36 se simplifica cu 3 si rezultatul final este 12.