Question

(6+12+18+24+........+6000)/(3+6+9+12+....+3000)=

Answer 1

primul sir:  (6000-6):6+1=5994:6+1=999+1=1000
al 2lea sir: (3000-3):3+1=2997:3+1=999+1=1000

raportul 1000/1000=1

Answer 2

Il scoatem pe 6 factor comun
6·(1+2+3+4+...+1000)+[3·(1+2+3+4+...+1000)=6·(1000·1001:2)+[3·(1000·1001:2)]=6·(1001000:2)·[3·(1001000:2)]=6·500050·(3·500050)=3000300+1500150=4500450

sper ca intelegi, sunt cam multe zerouri dar se intelege