Question

(6+2^10÷2^8)÷10^5-9×10

[(3^2)^5÷3^7-3^0-3^2]×4÷34+2^2
Va rog

Answer 1

(6+2^2):10^5- 90 = (6+4):10^5 - 90 = 10:10^5 - 90 = 10^(-4) - 90 = 1/10000 - 90 =

1/10000 - 900000/10000 = -899999/10000 = -89,999

[3^10: 3^7 - 1 - 9]x 4 :34 +4 = [3^3 - 10]x4 :34+4 = [27-10]x4 :34+4 = 17x4 :34+4 = 68:34+4 = 2+4 = 6