Question

(√6+√2)×√2 urgent varogg!!! :*

Answer 1

= radical 12 + radical 4
= 2× radical 3 + 2

Answer 2

$( \sqrt{6} + \sqrt{2} )* \sqrt{2} \\ = (\sqrt{2*3} + \sqrt{2} )* \sqrt{2} \\ =( \sqrt{2} * \sqrt{3} + \sqrt{2} )* \sqrt{2} \\ = \sqrt{2} ( \sqrt{3} +1)* \sqrt[]{2} \\ = \sqrt{ 2^{2} }( \sqrt{3} +1) \\ =2(\sqrt{3} +1)$