Question

(6-2)×8 ; 4×(3+6) rezolvare prin a doua metodă?

Answer 1

( 6 - 2 ) × 8 = 4 × 8 = 32 → primul mod

= 6 × 8 - 2 × 8 = 48 - 16 = 32 → al doilea mod

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4 × ( 3 + 6 ) = 4 × 9 = 36 → primul mod

= 4 × 3 + 4 × 6 = 12 + 24 = 36 → al doilea mod

Answer 2

(6-2)×8=
4×8=
32

(6-2)×8=
(6×8)-(2×8)=
48-16=
32

4×(3+6)=
4×9=
36

4×(3+6)=
(4×3)+(4×6)=
12+24=
36

Sper că te-am ajutat!❤