Question

( 6 + 2 la puterea 10 : 2 la puterea 8 ) : 10 la puterea 5 -9 x 10
DAU COROANA

Answer 1

Răspuns:

$(6 + {2}^{10} \div {2}^{8} ) \div {10}^{5} - 9 \times 10 = \\ (6 + {2}^{2} ) \div {10}^{5} - 90 = \\ 10 \div {10}^{2} - 90 = - 80$