Question

(6-2)la puterea5 :(8-6)³×(2017-15)la puterea 0:2017la puterea 0-1laputerea 2017

Answer 1

$(6-2)^5:(8-6)^3\cdot (2017-15)^0:2017^0-1^{2017}= \\ \\ =4^5:2^3\cdot 1:1-1\\ \\=(2^2)^5:2^3 \\ \\ =2^{10}:2^3-1\\ \\ = 2^{10-3}-1\\ \\ = 2^{7}-1\\ \\ = 128-1\\ \\ = \bold{127}$