Question

6. Aduceţi la forma cea mai simplă: [3x^2y^-3/z] ÷ (3x)^3z^-2/y^5​

Answer 1

Explicație pas cu pas:

$\dfrac{{3x}^{2} {y}^{- 3} }{z} \div \dfrac{{(3x)}^{3} {z}^{- 2} }{{y}^{5}} = {3x}^{2} {y}^{- 3}{z}^{ - 1} \div [{(3x)}^{3} {z}^{- 2} {y}^{ - 5}] = \\ = {3x}^{2} {y}^{- 3}{z}^{- 1} \cdot [{(3x)}^{ - 3} {z}^{2} {y}^{5}] = {3}^{1 - 3} {x}^{2 - 3} {y}^{ - 3 + 5} {z}^{ - 1 + 2} \\ = {3}^{ - 2} {x}^{ - 1} {y}^{2} {z}^{1} = \dfrac{ {y}^{2} z}{9x}$