Question

6.aflati cate nr nat. sunt cuprinse intre nr a si b, unde:
a=6+8×[32÷4-5×(4³-7×3²)]
b=15×2+(256÷16+4)÷5+2121÷21
7.puneti paranteze pt a obtine egalitati adv
a) 5×4÷2+8-2=48
b) 6×9÷3+5-2=36
c) 3×8÷4+6×2-18=24​

Answer 1

Răspuns:

Explicație pas cu pas:

a) a = 6+8x[32:4-5x(4^3-7x3^2)]
a =6+8x[32:4-5x(64-7x9)]
a =6+8x[32:4-5x(64-63)]
a =6+8x(8-5x1)
a =6+8x(8-5)
a =6+8x3

a =6+24

a = 30

b) b=15x2+(256:16+4):5+2121:21
b =15x2+(16+4):5+2121:21

b =15x2+(16+4):5+101

b=15x2+20:5+101

b=30+20:5+101

b=30+4+101

b=34+101

b=135

numerele cuprinse sunt: (31,32,33…..134)

134 - 31 + 1 = 104 numere

7) a) 5x4:2+8-2=48

5x(4:2+8)-2=48

5x(2+8)-2=48

5x10-2=48

50-2=48

b) 6x9:3+5-2=36

6x(9:3+5-2)=36

6x(3+5-2)=36

6x(8-2)=36

6x6 =36

c) 3x8:4+6x2-18=24

3x(8:4+6x2)-18=24

3x(2+12)-18=24

3x14-18=24

42-18=24