Question

6. Atla numerele necunoscute din expresiile de mai jos.
a. (x + 282-75): 2 = 104
c. 869-[(x + 112): 5+113]= 134 b.
b.x×4:10 + 101 = 133
d. 104: [(x - 3x 8) 2:8] = 13
dacă puteți prin metoda mersului invers​

Answer 1

Răspuns:

a)

$\bf (x + 282 - 75) : 2 = 104$

$\bf (x + 282 - 75) = 104 \cdot 2$

$\bf (x+282-75)=208$

$\bf x+282=208+75$

$\bf x+282=283$

$\bf x=283-282$

$\red{\underline{\bf x=1}}$

b)

$\bf x\cdot 4:10+101=133$

$\bf x\cdot 4:10=133-101$

$\bf x\cdot 4:10=32$

$\bf x\cdot 4=32\cdot10$

$\bf x\cdot 4=320$

$\bf x=320:4$

$\blue{\bf\underline{ x=80}}$          

c)

$\bf 869-[(x+112):5+113]=134$

$\bf 869=134+[(x+112):5+113]$

$\bf 869-134=[(x+112):5+113]$

$\bf 735=(x+112):5+113$

$\bf 735-113=(x+112):5$

$\bf 622=(x+112):5$

$\bf 622\cdot5=(x+112)$

$\bf 3110=x+112$

$\bf 3110-112=x$

$\bf \purple\underline{x= 2998}}$

d)

$\bf 104: [(x - 3\cdot 8) \cdot2:8] = 13$

$\bf 104=13\cdot [(x - 3\cdot 8) \cdot2:8]$

$\bf 104:13= (x - 3\cdot 8) \cdot2:8$

$\bf 8= (x - 3\cdot 8) \cdot2:8$

$\bf 8\cdot 8= (x - 3\cdot 8) \cdot2$

$\bf 64= (x - 3\cdot 8) \cdot2$

$\bf 64:2= (x - 3\cdot 8)$

$\bf 32= x - 3\cdot 8$

$\bf 32= x - 24$

$\bf 32+ 24=x$

$\bf \pink{\underline{x=56}}$

==pav38==