Question

6. Calculează, respectând regulile învăţate.
a) (224 +100:10) 0+129 =
b) 406 + 36:4 + 2 x 8-227 =
c) 328 +56:(80-73) * (7 +4-8) =​

Answer 1

Răspuns:

(224+100÷10)×0+129=129

=(224+10)×0+129

=234×0+129

=0+129

=129

406+36÷4+2×8-227=204

=406+9+16-227

=415+16-227

=431-227

=204

328+56÷(80-73)×(7+4+8)=352

=328+56÷(80-73)×3

=328+56÷7×3

=328+8×3

=328+24

=352