Question

6 • Ecuaţi şi sisteme de ecuatii d) Rezolvati, prin metoda reducerii, următoarele sisteme de ecuatii liniare: S a) x + 2 y = 11 2 x+1=3 y-7 18x - 2y = -2 13(x - y)+1=x+y-11 b) x + 3y = -10 S 6x +7 y = 4 {-x+2y=-5 1-2 x + 9 y=-24 [2x-3y= 7,5 3 x +11 y=-1 f) 5x + y=-4,1 -2 x + 9 y=17 e) c) Rezolvaţi, prin metoda reducerii, următoarele ajutorrrrr rapid va rogggg​

Answer 1

Răspuns:

liniare: a) x + 2 y = 11 /-2

2 x+1=3 y-7

-2x-4y=-22

2 x-3y=-7-1

0-7y=-30 y=30/7

x + 2 y = 11 /3

2x-3y=-8. /2

3x+6y=33

4x-6y=-16

7x+0. =17. x=17/7

18x - 2y = -2 /:2

13(x - y)+1=x+y-11

9x-y=-1

12x-14y=-12/:2

9x-y=-1. /-7

6x-7y=-6

-63x+7y=7

6x-7y=-6

57x+0=1

x=1/57

9x-y=-1. / 2

6x-7y=-6 /-3

18x-2y=-2

-18x+21y=18

0+19y=16

y=16/19