Question

6 la puterea a doua x minus cu 4 x plus 1 egal 0 ​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

"6 la puterea a doua x minus cu 4 x plus 1 egal 0 ​"

$\it 6x^2-4x+1=0 \Rightarrow 2x^2+4x^2-4x+1=0 \Rightarrow (4x^2-4x+1)+2x^2=0 \Rightarrow \\ \\ \Rightarrow \underbrace{\it(2x-1)^2+2x^2}_{>0}=0 \Rightarrow x_{1,2}\not\in\mathbb{R}$

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" ײ+3×+1=0 "

$\it x^2 +3x+1=0,\ a=1,\ b=3,\ c=1\\ \\ \Delta=b^2-4ac=3^2-4\cdot1\cdot1=9-4=5\\ \\ x_{1,2}=\dfrac{-b\pm\sqrt{\Delta}}{2a} \Rightarrow x_{1,2}=\dfrac{-3\pm\sqrt5}{2} \Rightarrow \begin{cases} \it x_1=\dfrac{-3-\sqrt5}{2}\\ \\ \it x_2=\dfrac{-3+\sqrt5}{2}\end{cases}$