Question

6 ORI (2N) / ( 2N-1)=N / N-3

Answer 1

$6* \frac{2n}{2n-1}=\frac{n}{n-3} \\\\ \frac{12n}{2n-1}=\frac{n}{n-3} \\\\ 12n(n-3)=n(2n-1) \\\\ 12n^2-36n=2n^2-n \\\\ 12n^2-2n^2-36n+n=0 \\\\ 10n^2-35n=0 \ \ \ |:5n \\\\ 2n-7=0 \\\\ 2n=7 \\\\ \boxed{n=\frac{7}{2}}$