Question

6 radical din 5 - 2 radical 5+(-4radical 5)=
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Answer 1

$6 \sqrt{5} - 2 \sqrt{5} + ( - 4 \sqrt{5} ) = 6 \sqrt{5} - 2 \sqrt{5} - 4 \sqrt{5} = (6 - 2 - 4) \sqrt{5} = (4 - 4) \sqrt{5} = 0 \sqrt{5} = 0$