Question

(6 radical din 6 - 7 radical din 2) ×2 radical din 2.​

Answer 1

$(6\sqrt{6}-7\sqrt{2})*2\sqrt{2}\\=6\sqrt{6}*2\sqrt{2}-7\sqrt{2}*2\sqrt{2}\\=12\sqrt{12}-7\sqrt{4}\\=12*2\sqrt{3}-7*2\\=24\sqrt{3}-14$