Question

6 radical din 6 supra 5 radical din 3 - 6 radical din 2
VA ROG dati si explicatie cum se face.

Answer 1

Mult succes în continuare !

Answer 2

$\it \dfrac{^{\sqrt3)}6\sqrt6}{\ \ 5\sqrt3}-6\sqrt2=\dfrac{6\sqrt{18}}{5\cdot3}-6\sqrt2= \dfrac{6\sqrt{9\cdot2}}{5\cdot3}-6\sqrt2= \dfrac{6\cdot3\sqrt{2}}{5\cdot3}-6\sqrt2=\\ \\ \\ =\dfrac{6\sqrt{2}}{5}-6\sqrt2=6\sqrt2\Big(\dfrac{1}{5}-1\Big)=6\sqrt2\cdot(-\dfrac{4}{5})=-\dfrac{24\sqrt2}{5}$

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$\it \dfrac{6\sqrt6}{5\sqrt3}-\ \ ^{5\sqrt3)}6\sqrt2= \dfrac{6\sqrt6-30\sqrt6}{5\sqrt3}=\dfrac{\ \ -24\sqrt6 ^{(\sqrt3}}{5\sqrt3}=-\dfrac{24\sqrt2}{5}$