Question

6/radical din2+2-radical din 18....Cat face va rog frumos

Answer 1

6/√2 + 2√18
6√2/(√2)^2 + 2•3√2
3√2 + 6√2
8√2

Answer 2

$\it \dfrac{^{\sqrt2)}6}{\ \ \sqrt2} +2-\sqrt{18} = \dfrac{6\sqrt2}{2} +2-\sqrt{9\cdot 2} =3\sqrt2+2-3\sqrt2=2$