Question

6. Să se afle a+b,unde a= 4√2×(-3√2)+25 şi b= 8√27: 2√3 - 13 ​

Answer 1

Răspuns: $\bf \red{\bf a+b =0}$

Explicație pas cu pas:

$\bf a = 4\sqrt{2} \cdot \big(-3\sqrt{2} \big)+25$

$\bf a = -4\cdot 3\cdot \sqrt{2} \cdot \sqrt{2}+25$

$\bf a = -12\cdot 2+25$

$\bf a = -24+25$

$\bf\purple{\underline{\underline{ a = 1}}}$

$\bf ~~$

$\bf b = 8\sqrt{27} : 2\sqrt{3} -13$

$\bf b = 8\sqrt{3^{3} } : 2\sqrt{3} -13$

$\bf b = 8\cdot 3\cdot \sqrt{3} : 2\sqrt{3} -13$

$\bf b = 24\cdot \sqrt{3} : 2\sqrt{3} -13$

$\bf b = 24:2\cdot \sqrt{3} : \sqrt{3} -13$

$\bf b = 12 -13$

$\bf \green{\underline{\underline{b = -1}}}$

$\bf ~$

$\bf a + b = 1 + (-1) \implies \red{\boxed{\bf a+b =0}}$

==pav38==

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