Question

6. Să se afle numărul natural x:
a) 3.r=x+2
c) 7x-3=6x
e) 5r-2+x=5x-1
g) 2(x+3) = r +14
i) 3(x+2)+3 = 2x +10
k) 4(x+3)+2(2x - 2) = 5x +14
m) 7x +5(x+3) - 10x = x + 20
o) 4(2x+3)-8=7(x+1)
b) 5x = 2x +9
d) 5x - 4= 2x +2
f) 5x+12 = 3x + 20
h) x +5+2(x-1)=x+19
j) 2(2x + 3) + 1 = 3(x +4)
1) 3(x + 2) + 2(x + 4) = 4x +29
n) 2(x + 5) - X+3(x - 1) = 35
OFER 22 DE PUNCTE SI COROANA PLS​

Answer 1

a) Are solutii infinite

c) 7x - 3 = 6x <=> 7x - 6x = 3 <=> x = 3

e) Are solutii infinite

g) Are solutii infinite

i) 3(x + 2) + 3 = 2x + 10 <=> 3x + 6 + 3 = 2x + 10 <=> 3x - 2x + 9 - 10 = 0 <=> x - 1 = 0 => x = 1

k) 4(x + 3) + 2(2x - 2) = 5x + 14 <=> 4x + 12 + 4x - 4 - 5x - 14 = 0 <=> 3x - 6 = 0 => x = 2

m) 7x + 5(x + 3) - 10x = x + 20 <=> 7x + 5x + 15 - 10x - x - 20 = 0 <=> x - 5 = 0 => x = 5

o) 4(2x + 3) - 8 = 7(x + 1) <=> 8x + 12 - 8 = 7x + 7 <=> 8x + 4 - 7x - 7 = 0 <=> x - 3 = 0 => x = 3

b) 5x = 2x + 9 <=> 3x = 9 <=> x = 3

d) 5x - 4 = 2x + 2 <=> 5x - 2x - 4 - 2 = 0 <=> 3x - 6 = 0 => x = 2

f) 5x + 12 = 3x + 20 <=> 5x - 3x + 12 - 20 = 0 <=> 2x - 8 = 0 => x = 4

h) x + 5 + 2(x - 1) = x + 19 <=> x + 5 + 2x - 2 - x - 19 = 0 <=> 2x - 16 = 0 => x = 8

j) 2(2x + 3) + 1 = 3(x + 4) <=> 4x + 6 + 1 = 3x + 12 <=> 4x - 3x + 6 + 1 - 12 = 0 <=> x - 5 = 0 => x = 5

1) 3(x + 2) + 2(x + 4) = 4x + 29 <=> 3x + 6 + 2x + 8 - 4x - 29 = 0 <=> x - 15 = 0 => x = 15

n) 2(x + 5) - x + 3(x - 1) = 35 <=> 2x + 10 - x + 3x - 3 - 35 = 0 <=> 4x - 28 = 0 => x = 7