Question

6. Să se calculeze:
a) 7- [3 - (10-15)]=
c) 43+[-15+(12-51)]=
e) 13-[-2+5-(-4+6-2)]=
g) -22+19+[(-1)+7-(-5)]=
i) -5-[-4+(2-7)]=
k) -34- (12-24)+[(-5-7)+9)=
m) -36+{-2 + [6+(-18-16)]} =
0) -13+{-17-[-31 +19-(-3)]} =
b) 17-[2-(-5+13)]=
d) 53-[-5-(3-18)]=
f) -15-[-12+(-3+7)]=
h) -36-(3-6)+(-5-3) =
j) - [6-(18-32)] + 27 =
1) 2-[-17 +(2-8) - 3] +(-17–39)=
n) - 14+{-6-3+[-6+(-5)])=​

Answer 1

Răspuns:

a) 7- [3 - (10-15)]=  7-[3-(-5)]=7-(3+5)=7-8=-1

c) 43+[-15+(12-51)]=  43+[-15+(-39)]=43+(-54)=-11

e) 13-[-2+5-(-4+6-2)]=  13-(3+0)=13-3=10

g) -22+19+[(-1)+7-(-5)]=  -3+(6+5)=-3+11=8

i) -5-[-4+(2-7)]=  -5-[-4+(-5)]=-5-(-9)=-5+9=4

k) -34- (12-24)+[(-5-7)+9)=  -34 - (-12)+[(-12)+9]=-34+12+(-3)=-22-3=-25

m) -36+{-2 + [6+(-18-16)]} = -36+{-2+[6+(-34)]}=-36+[-2+(-28)]=-36+(-30)=-66

0) -13+{-17-[-31 +19-(-3)]} =  -13+[-17-(-31+19+3)]= -13+[-17-(-9)]= -13+(-26)=-39

b) 17-[2-(-5+13)]=  17-[2-(+8)]=17-(-6)=17+6=23

d) 53-[-5-(3-18)]=  53-[-5-(-15)]=53-(-5+15)=53-10=43

f) -15-[-12+(-3+7)]= -15-(-12+4)=-15-(-8)=-23

h) -36-(3-6)+(-5-3) =  -36-(-3)+(-8)=-33-8=-41

j) - [6-(18-32)] + 27 =  - [6-(-14)]+27= - (6+14)+27= -20+27=7

1) 2-[-17 +(2-8) - 3] +(-17–39)=  2- [-17+(-6)-3]+(-56)=2-(-26)+(-56)=28+(-56)=-28

n) - 14+{-6-3+[-6+(-5)])=​ -14+[-9+(-11)]= -14+(-20)=-34

Explicație pas cu pas: