Question

6. Sa se rezolve in Z ecuațiile:
a) 21437;
d) 3(4-1)-6;
g) 2(x+2)-3x-6
D &r-16=0;
m) 4r+2= 30;
d) 9.2x 31 7x;
e) 3(x+1)-11 x;
h) 4x12 3(x+1) :
k) 5+x2=x+3;
n) 2(x+1)-10-x;
c) 7-2x 23 12x;
1 1 4(2x 1) 3(x+2)+1
i) 3 5(2x 1) 4(x+2)+1
1) |x1| 3;
0) 2+x-31-7.

Answer 1

Explicație pas cu pas:

m)

$4r+2= 30 \\ 4r = 30 - 2 \\ 4r = 28 \\ 4r = 28 \div 4 = > r = 7$