Question

6 și 7 vă rog frumos.. ^^

Answer 1

6)   [tex]5|x-y+3|+|-4|(y-2)^2=0\\ |x-y+3|\geqo\\ |-4|=4,(y-2)^2\geq 0 \rightarrow\\ x-y+3=0\\ y-2=0,\y=2\\ x=-3+2=-1[/tex]
7)  
 
[tex]2^{58}=(2^2)^{29}=4^{29}\ \textgreater \ 3^{29}\\ |2^{58}-3^{29}|=4^{29}-3^{29}\\ a=4^{29}-4^{29}+3^{29}=3^{29}\\ b=(-2)^{20}\cdot2^9=2^{20}\cdot2^9=2^{29}\\ a\ \textgreater \ b[/tex]