Question

6 si 7 va rog !urgent !dau coroana.multumesc

Answer 1

Explicație pas cu pas:

Sper ca te-am ajutat la tema și să înțelegi cum aduci factorii sub radical, este foarte ușor.

Answer 2

$\displaystyle 6.~a)~10\sqrt{2} =\sqrt{10^2 \cdot 2} =\sqrt{100 \cdot 2} =\sqrt{200} \\\\ b)~10\sqrt{3} =\sqrt{10^2 \cdot 3} =\sqrt{100 \cdot3} =\sqrt{300} \\\\ c)~10\sqrt{5} =\sqrt{10^2 \cdot 5} =\sqrt{100 \cdot 5} =\sqrt{500} \\\\ d)~10\sqrt{7} =\sqrt{10^2\cdot 7} =\sqrt{100 \cdot 7} =\sqrt{700}$

$\displaystyle7.~a)~6\sqrt{3}=\sqrt{6^2\cdot3}=\sqrt{36 \cdot 3}=\sqrt{108}\\\\ b)~5\sqrt{5}=\sqrt{5^2\cdot5}=\sqrt{25\cdot5}=\sqrt{125}\\\\c)~9\sqrt{2}=\sqrt{9^2 \cdot 2} =\sqrt{81\cdot2}=\sqrt{162}\\\\d)~4\sqrt{7}=\sqrt{4^2\cdot 7}=\sqrt{16\cdot 7}=\sqrt{112}\\\\e)~5\sqrt{6}=\sqrt{5^2\cdot6}=\sqrt{25\cdot6}=\sqrt{150}\\\\ f)~7\sqrt{3} =\sqrt{7^2\cdot3}=\sqrt{49\cdot 3}=\sqrt{147}\\\\ g)~6\sqrt{5}=\sqrt{6^2\cdot 5}=\sqrt{36\cdot 5}=\sqrt{180} \\\\h)~5\sqrt{7}=\sqrt{5^2\cdot7}=\sqrt{25\cdot7}=\sqrt{175}$