Question

6 supra 5: {3,25:26•1,(3)+5:2,(7)-[3,3(7):0,(304)-1 supra 3-10]}= Vă rog ajutațimă...

Answer 1

6/ 5: {3,25:26•1,(3)+5:2,(7)-[3,3(7):0,(304)-1 supra 3-10]}=
=6/5:[13/4 :26*4/3+5: 25/9 -( 304/90- 1/3 -10)]=
=6/5:[ 13/4*1/26*4/3 + 5*9/25 - ( 304/90 -30/90 -900/90)]=
=6/5: [ 1/6+9/5- ( -626/90)=6/5: (1/6+9/5 +626/90)=6/5:(15/90+162/90+626/90)
=6/5:803/90=6/5*90/803= 108/803

Answer 2

6 supra 5: {3,25:26•1,(3)+5:2,(7)-[3,3(7):0,(304)-1 supra 3-10]}= ?


3,25:26·1,(3)+5:2,(7) = (325/100):26· (4/3)+ 5:(25/9)=

= (325/100)·(1/26)·(4/3) +5·(9/25) =
 
= (13/4)·(1/26)·(4/3)+ (9/5) = 1/6+9/5 =59/30



3,3(7):0,(304)- 1/3-10 = (304/90)·(999/304) -1/3-10 =

 

=111/10 -1/3-10 =23/30

Exercițiul devine:

(6/5):(59/30 - 23/30) = (6/5) : (36/30) = (6/5) : (6/5)  =1